cubic solver
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09-08-2023, 02:26 PM
Post: #1
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cubic solver
This program solve x^3 = a*x + b, for x
Code: cubic_ab(a,b) := Code: cubic(a,b) := Michael Penn's example Let x = sin(θ) + cos(θ), it reduced to cubic: x^3 = 3*x - 11/8 Cas> r := cubic(3, -11/8) Cas> simplify(r) → [1/2, (3*√5-1)/4, (-3*√5-1)/4] Cas> float(Ans) → [0.5, 1.42705098312, −1.92705098312] Cas> float(r) → [1.42705098312, −1.92705098312, 0.5] We have Cas simplify bug here! symbolic and approximate numbers don't match. Luckily, the algorithm doesn't care which cube roots is used (no need for principle root). But, this bug should be fixed. Cas> b := cubic_ab(3, -11/8) [2] → (1/256*(-√15*48*i-176))^(1/3) Cas> polar(float(b)) → 1., −0.77627903074 Cas> polar(simplify(b)) → 1 , atan(√15) Simplify bug had phase angle off by 2*pi/3: Cas> atan(√15) - 2*pi/3.0 → −0.77627903074 |
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09-08-2023, 02:44 PM
Post: #2
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RE: cubic solver
Root simplify returned wrong (not principle) root bug existed for XCas 1.5.0
But, it is worse on XCas 1.9.0-31 (mingw32 win32) Result does not match phase *and* magnitude. XCas> b := (1/256*(-√15*48*i-176))^(1/3) XCas> polar(float(b)) 1.0, -0.77627903074 XCas> simplify(polar(b)) // good \(\displaystyle 1\;,\;\frac{-\pi +\arctan \left(\frac{3}{11} \sqrt{15}\right)}{3}\) XCas> simplify(polar(simplify(b))) // bad \(256\;,\;-\pi +\arctan \left(\frac{3}{11} \sqrt{15}\right)\) |
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09-08-2023, 06:56 PM
Post: #3
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RE: cubic solver
Yes, there is an additional check in recent versions of Xcas, and here it failed because an argument was not reduced mod 2*pi.
https://github.com/geogebra/giac/commit/...ea8fd94c9d |
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