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ierfc(z) : sign definition
11-20-2023, 12:41 PM
Post: #1
ierfc(z) : sign definition
Function ierfc(z)

Wolfram Alpha defines it as
z×erfc(z) - e^(-z²)/sqrt(pi)
and calculates accordingly.

At Wikipedia, French version,
of Function d'erreur, section "Extensions",
we find the reverse definition, ie:
e^(-z²)/sqrt(pi) - z×erfc(z).

Is there an "error" here?

What is the most common convention or the "correct" definition ?

Thanks for your answer.
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11-20-2023, 06:55 PM
Post: #2
RE: ierfc(z) : sign definition
(11-20-2023 12:41 PM)Gil Wrote:  Function ierfc(z)

Wolfram Alpha defines it as
z×erfc(z) - e^(-z²)/sqrt(pi)
and calculates accordingly.

WA probably wrong, since their own Wollfram Mathworld site has the sign reveresd, see erfc1(x)
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