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test new thread
05-24-2024, 07:26 AM
Post: #1
test new thread
The equation given by $y = mx + c$.

The integral from $a$ to $b$ of $x^2$ is:
$$
\int_{a}^{b} x^2 \, dx
$$

Here is a matrix:
$$
\begin{pmatrix}
a & b \\
c & d
\end{pmatrix}
$$

The sum of the first $n$ natural numbers is:
$$
\sum_{i=1}^{n} i = \frac{n(n+1)}{2}
$$

The product of the first $n$ natural numbers is:
$$
\prod_{i=1}^{n} i = n!
$$
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05-25-2024, 07:27 PM
Post: #2
RE: test new thread
The integral from \(a\) to \(b\) of \(x^2\) is:

\[
\int_{a}^{b} x^2 \, dx
\]

Here is a matrix:

\(
\begin{pmatrix}
a & b \\
c & d
\end{pmatrix}
\)

Quote this post to see how it is done.
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05-26-2024, 04:03 AM
Post: #3
RE: test new thread
(05-25-2024 07:27 PM)Thomas Klemm Wrote:  Here is a matrix:

\(
\begin{pmatrix}
a & b \\
c & d
\end{pmatrix}
\)

Using "bmatrix" instead of "pmatrix" yields square brackets:

\(
\begin{bmatrix}
a & b \\
c & d
\end{bmatrix}
\)

<0|ΙΈ|0>
-Joe-
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05-29-2024, 02:08 PM
Post: #4
RE: test new thread
Hooooooo

Thanks :-D
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