Complex conjugates
10-14-2014, 04:33 PM
Post: #1
 jefierro Junior Member Posts: 16 Joined: Oct 2014
Complex conjugates
Hi all, a pleasure to address so distinguish gentlemen.

I'm having difficulties in finding the answer I expect out of multiplying complex conjugates on the Prime, for example (3+2i)(3-2i) or (8-10i)(8+10i), as the rule state multiplying complex conjugates will give a real number 13 and 164 respectively from the examples above on the Prime CAS I get 3+2*i and 8-10*i Also on the HP35s I get the correct answer 13,i*0 164,i*0. What would I need to change on Prime for it to return the answer in the correct form?.

Thanks.
Jorge
10-14-2014, 04:50 PM
Post: #2
 Helge Gabert Senior Member Posts: 471 Joined: Dec 2013
RE: Complex conjugates
You are missing the multiplication symbol

(3+2*i)*(3-2*i) = 13 no problem.
10-14-2014, 04:55 PM
Post: #3
 jefierro Junior Member Posts: 16 Joined: Oct 2014
RE: Complex conjugates
OMG! i'm getting old.

Thanks.
10-14-2014, 04:57 PM
Post: #4
 Marcus von Cube Senior Member Posts: 760 Joined: Dec 2013
RE: Complex conjugates
(10-14-2014 04:33 PM)jefierro Wrote:  I'm having difficulties in finding the answer I expect out of multiplying complex conjugates on the Prime, for example (3+2i)(3-2i) or (8-10i)(8+10i)

Use the multiplication symbol instead of implicit multiplication and it should work. Implicit multiplication seems to be misinterpreted. You can see this in the left side of the history sometimes.

Marcus von Cube
Wehrheim, Germany
http://www.mvcsys.de
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