Complex conjugates

[jefierro]

Hi all, a pleasure to address so distinguish gentlemen.

I'm having difficulties in finding the answer I expect out of multiplying complex conjugates on the Prime, for example (3+2i)(3-2i) or (8-10i)(8+10i), as the rule state multiplying complex conjugates will give a real number 13 and 164 respectively from the examples above on the Prime CAS I get 3+2*i and 8-10*i Also on the HP35s I get the correct answer 13,i*0 164,i*0. What would I need to change on Prime for it to return the answer in the correct form?.

Thanks.
Jorge

[Helge Gabert]

You are missing the multiplication symbol

(3+2*i)*(3-2*i) = 13 no problem.

[jefierro]

OMG! i'm getting old.

Thanks.

[Marcus von Cube]

(10-14-2014 04:33 PM)jefierro Wrote:  I'm having difficulties in finding the answer I expect out of multiplying complex conjugates on the Prime, for example (3+2i)(3-2i) or (8-10i)(8+10i)

Use the multiplication symbol instead of implicit multiplication and it should work. Implicit multiplication seems to be misinterpreted. You can see this in the left side of the history sometimes.