Don't execute a function if a routine is called outside the program
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07-03-2015, 03:20 PM
(This post was last modified: 07-03-2015 03:35 PM by salvomic.)
Post: #1
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Don't execute a function if a routine is called outside the program
hi,
there is a way to don't execute a command if a function is not called inside the program, but externally (EXPORT...)? I've a code like this one: Code:
I would like to execute changeData(); only if ascendant() is called inside a program (to return to its menu, and so on) but not when the function is called externally (passing parameters...). In other words: the function should ask itself: "who is calling?"... Thank you Salvo ∫aL√0mic (IT9CLU) :: HP Prime 50g 41CX 71b 42s 39s 35s 12C 15C - DM42, DM41X - WP34s Prime Soft. Lib |
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07-03-2015, 06:22 PM
Post: #2
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RE: Don't execute a function if a routine is called outside the program
Salvo,
If I understand your question correctly, this should work: Code:
When you execute ascendant from the Home screen, changedata is not executed. When calling_program executes ascendant the flag "a" is set to 1 first and changedata is executed. You can't set "a" to 1 externally if you make it local. I don't know if the prime has user flags like the 48 thru 50g series has or not. I'm still learning HPPPL. Cheers, Road |
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07-03-2015, 06:27 PM
(This post was last modified: 07-03-2015 10:16 PM by salvomic.)
Post: #3
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RE: Don't execute a function if a routine is called outside the program
(07-03-2015 06:22 PM)roadrunner Wrote: Salvo, thanks Road, I'll try it; it seems a good workaround. Never I know if the Prime has user flags. I'll let you know then. Salvo EDIT: It worked, but I had to define a variable as global (internalfun:=0) to pass values through the routines... ∫aL√0mic (IT9CLU) :: HP Prime 50g 41CX 71b 42s 39s 35s 12C 15C - DM42, DM41X - WP34s Prime Soft. Lib |
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