(15C) Static Equivalent at a Point
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01-10-2016, 10:05 PM
Post: #1
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(15C) Static Equivalent at a Point
Link: http://edspi31415.blogspot.com/2016/01/h...point.html
Source: Step by Step Solutions for your HP Calculator: Engineering Applications. HP-32S. Hewlett Packard. Corvallis, OR. 1988 pg. 40-44 Equations: R5 * cos θ1 + R6 * cos θ2 = - Σ F * cos ϕ R5 * sin θ1 + R6 * sin θ2 = - Σ F * sin ϕ This program solves for R5, R6. Variables: Inputs: R0: number of points R1: T = angle of each known force (ϕ) R2: F = value of each known force (F) A = direction of the first reaction force (θ1) B = direction of the second reaction force (θ2) Outputs: R5: R1 = unknown force 1 (R1) R6: R2 = unknown force 2 (R2) Temporary Variables: R3, R4, R7, R8, R9, R.0 R3 = X = sin θ1 R9 = Y = cos θ1 R4 = C = sin θ2 R.0 = D = cos θ2 R7 = Σ F * cos ϕ R8 = Σ F * sin ϕ This program clears all the registers. Instructions: Enter n, press [ f ] [1/x] ( E ), then each pair of T then [R/S] and F then [R/S], respectively. When completed with the pair, enter A and B. R1 is displayed first. Press [R/S] to get R2. Program: Code:
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