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Pandigital e
12-28-2016, 11:40 AM
Post: #1
Pandigital e
This video presents a lovely pandigital approximation for Euler's e:






Pauli
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01-01-2017, 12:14 AM (This post was last modified: 01-01-2017 12:23 AM by Gerson W. Barbosa.)
Post: #2
RE: Pandigital e
Speaking of pandigital approximations,

Happy '5*EXP(6)-INV(LN(1039-EXP(-LN(2^(7-√4+8)))))' !

Not so lovely, but this should evaluate (almost) nicely on the wp34s (DBLOFF).

Gerson.
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01-01-2017, 12:42 AM
Post: #3
RE: Pandigital e
I've got a nice one that doesn't use any digits:

π →HR TANH TAN⁻¹ x²

Degrees mode only. Use FIX 0 or add an IP to the end.


Pauli
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01-01-2017, 03:32 AM (This post was last modified: 01-01-2017 03:33 AM by Gerson W. Barbosa.)
Post: #4
RE: Pandigital e
Not so accurate, but digits 1 through 9 in order (well, sort of):

'EXP(EXP(EXP(EXP(-.345678912))))-INV(π)+INV(π^π+INV(π)+e)+(π^π)^-π'
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01-01-2017, 08:32 AM
Post: #5
RE: Pandigital e
Okay, I'll use two sequential digits:

\( \lfloor 5 e^6 \rfloor \)
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01-01-2017, 08:43 AM
Post: #6
RE: Pandigital e
Or just unity but two levels of exponents:

\( \lfloor e^{10^{SINH^{-1}1}} \rfloor \)
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01-01-2017, 10:44 AM
Post: #7
RE: Pandigital e
(01-01-2017 08:43 AM)Paul Dale Wrote:  Or just unity but two levels of exponents:

\( \lfloor e^{10^{SINH^{-1}1}} \rfloor \)

Nice one-digit one! I still can't make it without all ten of them, though:

\(\lfloor 6.538472901! \rfloor \)
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01-01-2017, 11:03 AM
Post: #8
RE: Pandigital e
(01-01-2017 10:44 AM)Gerson W. Barbosa Wrote:  \(\lfloor 6.538472901! \rfloor \)

You don't need the 01 at the end Smile


Pauli
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01-01-2017, 11:04 AM
Post: #9
RE: Pandigital e
Or without all ten of them, twice:

'6.538472901!-EXP(-6.978245310)'
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01-01-2017, 11:10 AM
Post: #10
RE: Pandigital e
(01-01-2017 11:03 AM)Paul Dale Wrote:  
(01-01-2017 10:44 AM)Gerson W. Barbosa Wrote:  \(\lfloor 6.538472901! \rfloor \)

You don't need the 01 at the end Smile


Pauli

I know, but the family gathering would not be complete without the patriarchs :-)
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