Yet another new pi approximation

01142017, 05:57 PM
Post: #1




Yet another new pi approximation
\(e+\frac{69e^{2^{2}\ln \ln \left ( e^{e^{2}}+\ln \ln \left ( 2 \right ) \right )}}{163}\) 'e+(69e^(2^2*LN(LN(e^e^2+LN(LN(2))))))/163' 

01142017, 08:27 PM
Post: #2




RE: Yet another new pi approximation
I don't know... expressing one number with inifinite digits using another one? AFAIK, Euler once found a much more elegant way of linking Pi with e.


01142017, 10:48 PM
(This post was last modified: 01222017 07:14 PM by Gerson W. Barbosa.)
Post: #3




RE: Yet another new pi approximation
(01142017 08:27 PM)Maximilian Hohmann Wrote: I don't know... expressing one number with infinite digits using another one? AFAIK, Euler once found a much more elegant way of linking Pi with e. This is just an approximation starting from the fact that 163∙(π  e) ≃ 69, not an exact relationship in the realm of complex numbers like Euler's beautiful and wonderful formula. I think my correction term involving two levels of exponentiation and logarithm and the integer number 2 may have some aesthetic value, anyway beauty lies in the eyes of the beholder :)  Edited (22:Jan) The following doesn't require a wider HP50g screen to show the whole equation... ...but it does require a 16digit calculator to show the accuracy of approximation. 'e+(69e^(8/(1+1/(163*401))))/163' 

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