Wrong integral calculation

[tiamattia]

Today I was doing an exercise where I had to calculate a really simple integral. I was too lazy to do it so i took my Prime to solve it.
I had to calculate the integral of (((10e-12)^2)/f)*df from 10 to 198e3.

I get the same result in cas and in home: 661.2397e-24
The correct result is: 989.3437e-21

This is quite bad. What's happening?

[Arno K]

Annoying bug, I tried that and got your wrong result, if you take that factor outside the integral, better before, as a constant factor, you get the correct result.
Arno

[parisse]

During the computation of the quadrature on the first subdivision, one of the error estimates is about 1e-24, and considered to be 0, therefore the result of this first approximation is returned.