Bitwise AND with a variable

[Stevetuc]

If i perform an AND between 2 integers it is bitwise:

#160d AND #FFFFh gives result #160d

If one input is a real then the result is 1 if both input nonzero:
160 AND #FFFFh gives result 1

So far so good. However:
x:=#160d
x AND #FFFFh gives result 1 even though x has an integer value.
How can one perform a bitwise AND between integer variables?

[Didier Lachieze]

Use the BITAND function rather than the AND function: BITAND(x,#FFFFh)

(see the integer function list page 604 of the User Guide)

[Carlos295pz]

It is true that the integers in HP Prime can be adjusted to bits, but it manipulates as numeric data, almost equal to real, AND does its common work by returning 1 or 0.

[cyrille de brébisson]

Hello,

Make sure that the object stored in your variable is indeed a binary number.
lower case x is most likely a cas variable. CAS does not support binaries, so they will be a binary to real transform along the way.

If you create a home, non-typed variable (use global, or program variable), then you should be able to store your #160d in it and it will stay an integer.

Cyrille