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[48] how to simplify derivative?
07-16-2023, 08:53 AM
Post: #2
RE: [48] how to simplify derivative?
I assume that you are familiar with calculating the derivative on the HP-48G:

\(
\begin{matrix}
\frac{\mathrm{d} }{\mathrm{d} x} \frac{\sin(x))}{1 + \cos(x)} = \frac{\cos(x)}{1 + \cos(x)}-\frac{\sin(x) \left(-\sin(x)\right)}{\left(1 + \cos(x)\right)^2} \\
\end{matrix}
\)

We have to cheat a bit and use the following identities:

\(
\begin{matrix}
\sin(x)^2 + \cos(x)^2 &=& 1 \\
\left(1 + \cos(x)\right)^2 &=& \left(1 + \cos(x)\right) \cdot \left(1 + \cos(x)\right)
\end{matrix}
\)

Therefore we put everything on the stack for the later substitutions:

3: 1
2: '(1+COS(X))*(1+COS(X))'
1: 'COS(X)/(1+COS(X))-SIN(X)*-SIN(X)/(1+COS(X))^2'


Now we can enter the equation editor by pressing the ▼ key.
Select the expression \(\left(1 + \cos(x)\right)^2\) and use REPL to replace it with \(\left(1 + \cos(x)\right) \cdot \left(1 + \cos(x)\right)\).

Select this whole expression:

\(
\begin{matrix}
\frac{\sin(x) \left(-\sin(x)\right)}{\left(1 + \cos(x)\right) \cdot \left(1 + \cos(x)\right)}
\end{matrix}
\)

Use ←A to associate left which leaves us with:

\(
\begin{matrix}
\frac{\cos(x)}{1 + \cos(x)}-\frac{\frac{\sin(x) \left(-\sin(x)\right)}{\left(1 + \cos(x)\right)}}{\left(1 + \cos(x)\right)}
\end{matrix}
\)

Use ←→ to commute the arguments:

\(
\begin{matrix}
\frac{\cos(x)}{1 + \cos(x)}-\text{inv}\left(1 + \cos(x)\right) \frac{\sin(x) \left(-\sin(x)\right)}{\left(1 + \cos(x)\right)}
\end{matrix}
\)

We do the same on the left expression as well:

\(
\begin{matrix}
\text{inv}\left(1 + \cos(x)\right) \cdot \cos(x) -\text{inv}\left(1 + \cos(x)\right) \cdot \frac{\sin(x) \left(-\sin(x)\right)}{\left(1 + \cos(x)\right)}
\end{matrix}
\)

This allows using ←M to merge-factors-left:

\(
\begin{matrix}
\text{inv}\left(1 + \cos(x)\right) \cdot \left(\cos(x) - \frac{\sin(x) \left(-\sin(x)\right)}{\left(1 + \cos(x)\right)}\right)
\end{matrix}
\)

Now we can use AF to add the fractions:

\(
\begin{matrix}
\text{inv}\left(1 + \cos(x)\right) \cdot \frac{\left(\left(1 + \cos(x)\right) \cdot \cos(x) - \sin(x) \left(-\sin(x)\right)\right)}{\left(1 + \cos(x)\right)}
\end{matrix}
\)

We use ←D to distribute-left the expression: \(\left(1 + \cos(x)\right) \cdot \cos(x)\) to end up with:

\(
\begin{matrix}
\text{inv}\left(1 + \cos(x)\right) \cdot \frac{1 \cdot \cos(x) + \cos(x) \cdot \cos(x) - \sin(x) \left(-\sin(x)\right)}{\left(1 + \cos(x)\right)}
\end{matrix}
\)

With COLCT we can clean that up a bit:

\(
\begin{matrix}
\text{inv}\left(1 + \cos(x)\right) \cdot \frac{\cos(x)^2 + \sin(x)^2 + \cos(x)}{\left(1 + \cos(x)\right)}
\end{matrix}
\)

Now we substitute \(\cos(x)^2 + \sin(x)^2\) by \(1\) using the REPL command again:

\(
\begin{matrix}
\text{inv}\left(1 + \cos(x)\right) \cdot \frac{1 + \cos(x)}{\left(1 + \cos(x)\right)}
\end{matrix}
\)

We can now use COLCT on the fraction and then on the whole expression and end up with:

\(
\begin{matrix}
\frac{1}{1 + \cos(x)}
\end{matrix}
\)

The result is then:

1: '1/(1+COS(X))'


Conclusion

The equation writer is severely limited:
  • the ←M command works only for multiplication but not for division
  • the AF command doesn't consider the least common denominator
  • I haven't figured out a way to expand \((a+b)^2\) to \((a+b)(a+b)\)
  • it doesn't know about trigonometric identities

This makes it close to useless.
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Messages In This Thread
[48] how to simplify derivative? - grbrum - 07-15-2023, 09:11 PM
RE: [48] how to simplify derivative? - Thomas Klemm - 07-16-2023 08:53 AM



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