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HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x'
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HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x'
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HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x'
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11-08-2023, 07:52 AM
(This post was last modified: 11-08-2023 07:55 AM by klesl.)
Post: #6
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RE: HP50 : integral of '0^x' gives induly '?`
small corerction: int(a^x)=a^x/ln(a) for a>0
There is no way how to compute int(a^x,x) for a=0 because you need to rewrite a^x as e^(x*ln(a)) and logarithm is defined for a>0 only. This integral isn't equal to constant, it is undef as logarithm. Also you don't find int(a^x,x) for a=0 in any math tables. |
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| Messages In This Thread |
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HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x' - Gil - 11-06-2023, 05:05 PM
RE: HP50 : integral of '0^x' gives induly '?` - rawi - 11-07-2023, 02:38 PM
RE: HP50 : integral of '0^x' gives induly '?` - rawi - 11-07-2023, 03:11 PM
RE: HP50 : integral of '0^x' gives induly '?` - klesl - 11-07-2023, 03:28 PM
RE: HP50 : indefinite integral of '0^x' gives '?' and 0 for '0*x' - Gil - 11-07-2023, 09:30 PM
RE: HP50 : integral of '0^x' gives induly '?` - klesl - 11-08-2023 07:52 AM
RE: HP50 : integral of '0^x' gives induly '?` - Gil - 11-08-2023, 09:14 AM
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