Helix Arc Length
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11-29-2018, 09:22 AM
Post: #3
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RE: Helix Arc Length
...or, if you want to do it by integration, parameterise the curve as
\[x=r\cos\theta\qquad y=r\sin\theta\qquad z={l\over2\pi}\theta\] where \(r\) is the radius and \(l\) is the distance between one turn and the next. The square root in your integral is \[\sqrt{r^2+{l^2\over 4\pi^2}}\] which is a constant. Integrate over \(\theta\) from \(\theta=0\) to \(2\pi\) and you get the length of one turn; then multiply by the number of turns. Nigel (UK) |
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Messages In This Thread |
Helix Arc Length - ArPEn - 11-29-2018, 02:56 AM
RE: Helix Arc Length - ijabbott - 11-29-2018, 08:45 AM
RE: Helix Arc Length - Nigel (UK) - 11-29-2018 09:22 AM
RE: Helix Arc Length - ArPEn - 11-30-2018, 03:10 AM
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