'√√√√(2*√2*π*(10^3*(10^3+π/3^4)+1/(π*(π^5+π^2+1)+1/(√(2*π)))))' [NT]

[Gerson W. Barbosa]

(02-19-2020 02:51 AM)Paul Dale Wrote:  I mis-parsed the parenthesis placement
Fixed now.

Yes, too many parentheses. Quite easy to get lost, that’s why I used the HP 50g (m48+ emulator) Equation Editor.

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\( \sqrt {\sqrt {\sqrt {\sqrt {2π \sqrt{2} \left( 10^3 \left( 10^3+\frac{π}{3^4} \right)+\frac{1}{π \left(π^5+π^2+1 \right)+\frac{1}{\sqrt{2 π}}}\right) }}}}\)

Using only one-digit mantissas, the digits 0 through 5, π, the square root symbol and two pairs of parentheses to yield the first 17 digits of e. If I were mean, I would have posted this as a mini-challenge :-)