(PC-12xx~14xx) qthsh Tanh-Sinh quadrature
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04-15-2021, 10:38 PM
(This post was last modified: 04-16-2021 01:15 PM by Albert Chan.)
Post: #58
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RE: (PC-12xx~14xx) qthsh Tanh-Sinh quadrature
(04-15-2021 09:29 PM)robve Wrote: The derivation to select d=700 for the integrand exp(-0.01*y) is clear, except for the My aim is to pick d such that \(\int_0^d\) covered bulk of the area, less work for \(\int_d^∞\) Based on experience with plots, if value is below 1/1000 of peak, it seems to touch the x-axis. Actual number is not that critical. Hitting exact 100 is just lucky. lua> Q = require 'quad' lua> f2 = function(x) return exp(-0.01*x) end lua> for d=500,1500,100 do print(d, Q.quad(Q.count(f2), 0, huge, d), Q.n) end 500 99.99999999999997 71 600 100 71 700 100 71 800 99.99999999999997 71 900 99.99999999999999 71 1000 99.99999999999997 71 1100 99.99999999999997 71 1200 99.99999999999997 71 1300 99.99999999999999 71 1400 99.99999999999996 71 1500 99.99999999999997 71 Note that we could accomplish the same by compressing the function, by factor d lua> x, d = 20, 512 lua> f2(x) * 100 -- exact result, for \(\int_x^∞\) 81.87307530779819 lua> f3 = function(d) return function(x) return f2(x*d)*d end end lua> Q.quad(Q.count(f3(d)), x/d, huge/d), Q.n 81.87307530779817 69 lua> Q.quad(Q.count(f2), x, huge, d), Q.n 81.87307530779817 69 Both expressions are equivalent (because I picked d = power-of-2) But setting d is cost free, and less messy. |
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