Automatic differentiation using dual numbers

[Thomas Klemm]

(07-07-2022 07:40 AM)Ángel Martin Wrote:  By definition \(\varepsilon^2 = 0\)., right?

If we want to extend the idea of dual numbers for higher order derivatives we can define \(\varepsilon^n = 0\).
Slightly sloppy, we ignore the terms of \(\varepsilon^n\) and higher.