trigcos() function
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11-04-2014, 12:40 PM
Post: #1
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trigcos() function
s:=√((sin(t))²+(-cos(t)+1)²)
k:=expand(s) ---> √(-2*cos(t)+(cos(t))²+1+(sin(t))²) trigcos(√(-2*cos(t)+(cos(t))²+1+(sin(t))²)) ---> √(-2.*cos(t)+2.) trigcos(k) ---> 2.*ABS(sin(0.5*t)) With both trigcos() cases the same, why the additional simplification on trigcos(k)? How can I get the trigcos(k) result: √(-2.*cos(t)+2.)? Thanks, -Dale- |
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trigcos() function - DrD - 11-04-2014 12:40 PM
RE: trigcos() function - parisse - 11-04-2014, 02:22 PM
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