{ Vars List} how to store a value in one var of the list ?

[josephec]

(02-05-2014 12:42 PM)Snorre Wrote:  You could try an EXPR("A1:="+value); or in your case EXPR(L1(k)+":="+value);

ohhh YES!!!, that works perfect... even I already used the powerfull EXPR command to call programs with arguments.

Quote:Why is it so important to store your values in distinct variables?

Well is a program to solve Differential Equations, n equations really, may be 2, 3 o more that user enter in a list {Fj(T, U1, U2.. Un)} an example for n=3 {'U2+U1*T', 'T+U3', 'U2+U3'} so.. dynamically I create variables {'U1','U2', U3'} then I store some values in Uj and evaluate in the approx(Fj)... it could be solver declaring U1... U10
that is enough but a of powerfull calculator and good program are done to manage n equations/variables with no limits.

Thanks so much for you help... yesterday i tried EXPR("L(i):=...") and really i need to separate L(i).

Best regards!!
jose