Happy Pi Day!

[Joe Horn]

(03-15-2017 03:57 PM)Gerson W. Barbosa Wrote:  

(03-15-2017 11:04 AM)franz.b Wrote:  355/113 is enough for me B-)

That's perhaps the most efficient rational approximation for \(\pi\): six digits in a mnemonic sequence giving seven correct digits.

Here's an even better one:

\(\frac{190187072856692307609014394471477033962159076831354633719252611556270433​96809635643200078081079293702997523451876888357413870030368533612856711580598677​02399073227994426905220194699766118756059055619036488502928002591}{6053842551464​20326102361023215940531716391478150345020739231253172134740688232476946000058713​77454979656144746826774641287402271754410094658714414873962680343513347328160666​3121381125761746030151344353855924025288111}\)

That's 433 digits (217 digits over 216 digits) that returns 435 digits of pi. Converting the above into a mnemonic is left as an exercise for the student.