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'√√√√(2*√2*π*(10^3*(10^3+π/3^4)+1/(π*(π^5+π^2+1)+1/(√(2*π)))))' [NT]
02-18-2020, 10:13 PM (This post was last modified: 02-18-2020 11:59 PM by Gerson W. Barbosa.)
Post: #4
RE: '√√√√(2*√2*π*(10^3*(10^3+π/3^4)+1/(π*(π^5+π^2+1)+1/(√(2*π)))))' [NT]
(02-18-2020 10:00 PM)Paul Dale Wrote:  \( \sqrt {\sqrt {\sqrt {\sqrt {2π \sqrt{2} \left( 10^3 \left( 10^3+\frac{π}{3^4} \right)+\frac{1}{π \left(π^5+π^2+1 \right)}+\frac{1}{\sqrt{2 π}}\right) }}}}\)

Looks like the algebraic expression has been incorrectly parsed. As it is above, half the correct digits are lost. The HP 50g parses it right, but obviously it will show e to only 12 digits.

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\[\sqrt[16]{2\pi\sqrt{2} \left \{ 10^{3}\left ( 10^{3}+\frac{\pi }{3^{4}} \right )+\left [ \pi \left ( \pi ^{5}+\pi ^{2} +1\right )+\frac{1}{\sqrt{2\pi }} \right ]^{-1} \right \}}=e-5.29\times 10^{-17}\]
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≈e [NT] - Massimo Gnerucci - 02-18-2020, 07:38 PM
RE: '√√√√(2*√2*π*(10^3*(10^3+π/3^4)+1/(π*(π^5+π^2+1)+1/(√(2*π)))))' [NT] - Gerson W. Barbosa - 02-18-2020 10:13 PM



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