Need help for some HP Prime calculus/functions

[toml_12953]

(12-22-2019 09:49 PM)CyberAngel Wrote:  

(12-22-2019 07:47 PM)toml_12953 Wrote:  All of my Primes (HW A, two HW C (old and new keyboard) and D) had Trig Explorer 2 and 3 on them. I deleted all of them. Am I the only one who ended up with multiple Explorers?

Yes, yes you are--- ;-)

Good! I feel so special!

[Nigel (UK)]

(12-22-2019 07:36 PM)Devil69 Wrote:  Hi Nigel thank you very much I followed your instructions and it finally worked!
I think HP should add the variable "k" for trig (in)equations in their future update to do these operations without assume() function so that the answer looks like this:
x>π/6+2kπ and x<5π/6+2kπ, k∈ℤ

Glad to help. I agree with you about including an integer in the solution. The strange thing is that the Prime already does this when solving trigonometric equations: try solving \(\sin(x)=\frac12\), with "Principal" unticked in the CAS settings. So the mechanism is there, but for some reason it isn't applied to inequalities.

Nigel (UK)

[Devil69]

(12-23-2019 10:06 AM)Nigel (UK) Wrote:  

(12-22-2019 07:36 PM)Devil69 Wrote:  Hi Nigel thank you very much I followed your instructions and it finally worked!
I think HP should add the variable "k" for trig (in)equations in their future update to do these operations without assume() function so that the answer looks like this:
x>π/6+2kπ and x<5π/6+2kπ, k∈ℤ

Glad to help. I agree with you about including an integer in the solution. The strange thing is that the Prime already does this when solving trigonometric equations: try solving \(\sin(x)=\frac12\), with "Principal" unticked in the CAS settings. So the mechanism is there, but for some reason it isn't applied to inequalities.

Nigel (UK)

After unticking Pricipal in CAS settings and trying to solve \(\sin(x)=\frac12\), I have this result:

(12*n_24*π+π)/6, (12*n_24*π+5*π)/6, what does mean 12*n_24*π ?

Thanks

[Aries]

12*k*pi
Best,

Aries

[Nigel (UK)]

(12-23-2019 09:30 PM)Devil69 Wrote:  

(12-23-2019 10:06 AM)Nigel (UK) Wrote:  Glad to help. I agree with you about including an integer in the solution. The strange thing is that the Prime already does this when solving trigonometric equations: try solving \(\sin(x)=\frac12\), with "Principal" unticked in the CAS settings. So the mechanism is there, but for some reason it isn't applied to inequalities.

Nigel (UK)

After unticking Pricipal in CAS settings and trying to solve \(\sin(x)=\frac12\), I have this result:

(12*n_24*π+π)/6, (12*n_24*π+5*π)/6, what does mean 12*n_24*π ?

Thanks

n_24 is an arbitrary integer. If you run the command again you should get n_25 in the answer, and so on. This is better than using n or c or k, as these are common variable names which might already be in use elsewhere.

Nigel (UK)

[Devil69]

(12-24-2019 07:30 AM)Aries Wrote:  12*k*pi
Best,

Aries

Quote: n_24 is an arbitrary integer. If you run the command again you should get n_25 in the answer, and so on. This is better than using n or c or k, as these are common variable names which might already be in use elsewhere.

Alright then thanks for your help guys and have a nice Xmas Eve!

[Aries]

(12-24-2019 03:53 PM)Devil69 Wrote:  

(12-24-2019 07:30 AM)Aries Wrote:  12*k*pi
Best,

Aries

Quote: n_24 is an arbitrary integer. If you run the command again you should get n_25 in the answer, and so on. This is better than using n or c or k, as these are common variable names which might already be in use elsewhere.

Alright then thanks for your help guys and have a nice Xmas Eve!

Happy XMas to you too and everyone !
Best,

Aries