Different behavior of ./ and .* with vectors [SOLVED]
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04-29-2017, 04:22 PM
(This post was last modified: 02-02-2018 08:44 PM by JMB.)
Post: #1
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Different behavior of ./ and .* with vectors [SOLVED]
When both operands of .* or ./ are vectors of the same dimensions, both functions work accordingly:
[2,4] .* [2,4] → [4,16] [2,4] ./ [2,4] → [1,1] But when the first operand is a number they behave in a different way: 4 .* [2,4] → [8,16] 4 ./ [2,4] → Error: Invalid dimension In this case the operator * (without the dot), also works: 4 * [2,4] → [8,16] As a workaround for 4 ./ [2,4] one can use: 4 .* [2,4] .^ (-1) → [2,1] 4 * [2,4] .^ (-1) → [2,1] Is this the intended behavior, or should 4 ./ [2,4] also return [2,1] ? |
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05-01-2017, 04:19 PM
Post: #2
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RE: Different behavior of ./ and .* with vectors
Thanks, we'll put it on the list to investigate.
TW Although I work for HP, the views and opinions I post here are my own. |
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05-01-2017, 05:34 PM
Post: #3
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RE: Different behavior of ./ and .* with vectors
Thank you for your time, Tim!
I have noticed now that 4 ./ [2,4] returns the expected result [2,1] in CAS mode. |
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05-02-2017, 09:11 PM
(This post was last modified: 05-03-2017 06:39 PM by compsystems.)
Post: #4
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RE: Different behavior of ./ and .* with vectors
the Hadamard operations (Hadamard Product .*, Hadamard Power .^, Hadamard Inverse .^-1 and Division ./ ) are Element by Element
https://en.wikipedia.org/wiki/Hadamard_p...(matrices) the two arguments must be an array although the math kernel can expand functionality with scalars array vs matrix(linear algebra) operations https://www.mathworks.com/help/matlab/ma...tions.html HP50 & HPPRIME CAS MODE hadamard([[1,2],[3,4]],[[3,4],[5,6]]) RETURNS [[3,8],[15,24]] // OK HP50 hadamard([1,2],[3,4]) RETURNS [3,8] // ok hadamard([[1,2]],[[3,4]]) RETURNS [[3,8]] // ok HPPRIME CAS MODE hadamard([1,2],[3,4]) RETURNS 5*√5 WHY? hadamard([[1,2]],[[3,4]]) RETURNS [[3,8]] [1,2] .* [3,4] RETURNS [3,8] 4 ./ [2,4] -> [2,1] [4] ./ [2,4] -> [2] /!\ Resize to a smaller size [2,4] ./ [4] -> [1/2] 4 .* ([2,4] .^ -1) -> [2,1] 4./[2,4] -> 4.0 / [2,4] -> 4./[2,4] ? Without spaces also should operate to each element, as some point operations are equivalent to natural operators like [+] [-] [/] |
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02-02-2018, 08:44 PM
Post: #5
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RE: Different behavior of ./ and .* with vectors
Corrected in firmware 13333.
Thanks to the HP Prime Team! |
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