Could anybody help me with solving this equation?
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12-13-2024, 09:18 PM
Post: #1
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Could anybody help me with solving this equation?
I got a equation here and I don't know why I cannot solve for it, I attached the formula I input in the picture.
I really appreiate any help. |
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12-14-2024, 03:38 PM
Post: #2
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RE: Could anybody help me with solving this equation?
Try replacing approximate number 0.01 as 1/100
Cas> m1 := [[-p1*t1+1, t1], [-p1^2*t1, p1*t1+1]] Cas> solve([-m1(1,1)/-m1(2,1)=50, -m1(2,1)=1/100], [p1,t1]) {[1/150, 225]} Or, do this symbolically, then replace with approx. numbers Cas> solve([-m1(1,1)/-m1(2,1)=a, -m1(2,1)=b], [p1,t1]) (a=50, b=0.01) {[6.66666666667e−3, 225.]} |
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12-15-2024, 06:09 AM
Post: #3
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RE: Could anybody help me with solving this equation?
Solve it manually:
\( \begin{align} \frac{-(-pt+1)}{-(-p^2t)}&=50 \\ -(-p^2t)&=\frac{1}{100} \\ \end{align} \) Plug 2nd equation into 1st: \( \begin{align} pt-1&=\frac{50}{100} \\ p^2t&=\frac{1}{100} \\ \end{align} \) Add 1 on both sides of 1st equation: \( \begin{align} pt&=\frac{150}{100} \\ p^2t&=\frac{1}{100} \\ \end{align} \) Plug 1st equation into 2nd: \( \begin{align} pt&=\frac{150}{100} \\ p&=\frac{1}{150} \\ \end{align} \) Plug 2nd equation into 1st: \( \begin{align} t&=\frac{150^2}{100}=15^2=225 \\ p&=\frac{1}{150} \\ \end{align} \) |
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