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Could anybody help me with solving this equation?
12-13-2024, 09:18 PM
Post: #1
Could anybody help me with solving this equation?
I got a equation here and I don't know why I cannot solve for it, I attached the formula I input in the picture.

I really appreiate any help.


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12-14-2024, 03:38 PM
Post: #2
RE: Could anybody help me with solving this equation?
Try replacing approximate number 0.01 as 1/100

Cas> m1 := [[-p1*t1+1, t1], [-p1^2*t1, p1*t1+1]]
Cas> solve([-m1(1,1)/-m1(2,1)=50, -m1(2,1)=1/100], [p1,t1])

{[1/150, 225]}

Or, do this symbolically, then replace with approx. numbers

Cas> solve([-m1(1,1)/-m1(2,1)=a, -m1(2,1)=b], [p1,t1]) (a=50, b=0.01)

{[6.66666666667e−3, 225.]}
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12-15-2024, 06:09 AM
Post: #3
RE: Could anybody help me with solving this equation?
Solve it manually:

\(
\begin{align}
\frac{-(-pt+1)}{-(-p^2t)}&=50 \\
-(-p^2t)&=\frac{1}{100} \\
\end{align}
\)

Plug 2nd equation into 1st:

\(
\begin{align}
pt-1&=\frac{50}{100} \\
p^2t&=\frac{1}{100} \\
\end{align}
\)

Add 1 on both sides of 1st equation:

\(
\begin{align}
pt&=\frac{150}{100} \\
p^2t&=\frac{1}{100} \\
\end{align}
\)

Plug 1st equation into 2nd:

\(
\begin{align}
pt&=\frac{150}{100} \\
p&=\frac{1}{150} \\
\end{align}
\)

Plug 2nd equation into 1st:

\(
\begin{align}
t&=\frac{150^2}{100}=15^2=225 \\
p&=\frac{1}{150} \\
\end{align}
\)
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